ESTIMATING THE QUANTITY OF MATERIALS REQUIRED FOR 1 CUBIC METER CONCRETING

FOR 1 CUBIC METER CONCRETING OF MIX DESIGN M 25

WET VOLUME = 1m x 1m x 1m = 1 cubic meter

DRY VOLUME = wet volume + 54% of wet volume = 1+ (54/100 x 1) = 1 + 0.54 = 1.54

Now for M25 design mix

Mix ratio = 1:1:2 (CEMENT: FINE AGGREGATES: COURSE AGGREGATES)

Sum of ratio = 1+1+2= 4

Wet volume = 1 cubic meter

Dry volume = 1.54 x 1 = 1.54

Calculation for cement

Density of cement = 1440 kg per cubic meter

Weight of 1 bag of cement = 50 kg

Quantity of cement bags required for M25 grade for 1 cubic meter work

(1 x 1.54 x 1440) / (4 x 50) = 11.09 bags

Quantity of fine aggregates i.e. sand

= (1 x 1.54)/4 = 0.385 cubic meter

Quantity of course aggregates

= (2 x 1.54)/4 = 0.77 cubic meter

Similarly, for all mix design we can calculate quantity of materials required. Below is the table showing quantity of materials required for important mix design ratios.

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MIX DESIGN	CEMENT (in BAGS)	SAND (In cubic meter)	AGGREGATE (In cubic meter)
M 10 (1:4:8)	3.411692	0.473846	0.947692
M 15 (1:2:4)	6.336	0.44	0.88
M 20 (1:1.5:3)	8.064	0.42	0.84
M 25 (1:1:2)	11.088	0.385	0.77
M 30 (1:0.75:1.5)	13.64677	0.355385	0.710769

THE NUMBER OF CEMENT BAGS CAN BE ROUNDED OF i.e. FOR EXAMPLE IN M10 DESIGN MIX TAKE 4BAGS OF CEMENT.